Questions in category: 不定积分 (Indefinite Integral)
分析 >> 数学分析 >> 不定积分
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21. 求不定积分 $\int\frac{x+\sin x}{1+\cos x}dx$.

Posted by haifeng on 2016-02-20 00:50:48 last update 2016-02-20 00:50:48 | Answers (1) | 收藏


求不定积分

\[
\int\frac{x+\sin x}{1+\cos x}dx.
\]

22. $\int(1+x-\frac{1}{x})e^{x+\frac{1}{x}}dx$

Posted by haifeng on 2015-03-03 10:44:53 last update 2015-03-03 13:31:43 | Answers (0) | 收藏


\[
\int(1+x-\frac{1}{x})e^{x+\frac{1}{x}}dx
\]


[Hint]

考虑 $de^{x+\frac{1}{x}}$, 然后可以迅速找到被积函数的原函数.

23. 求 $\int e^{x^n}dx$

Posted by haifeng on 2015-02-11 15:36:20 last update 2015-02-11 15:36:20 | Answers (0) | 收藏


\[\int e^{x^n}dx\]

 

24. 求不定积分 $\int\sqrt{1+x^2}dx$

Posted by haifeng on 2015-01-16 21:59:32 last update 2020-11-17 10:50:26 | Answers (1) | 收藏


求不定积分

\[\int\sqrt{1+x^2}dx\]

 

 

[Hint] 碰到根号, 通常我们需要想办法将之去掉. 一个办法是令 $x=\tan t$, 另一个是令 $x=\sinh t$.

25. 求不定积分 $\int\sqrt{\frac{e^x-1}{e^x+1}}dx$

Posted by haifeng on 2015-01-12 14:11:16 last update 2015-01-12 14:11:16 | Answers (1) | 收藏


求不定积分

\[
\int\sqrt{\frac{e^x-1}{e^x+1}}dx.
\]

26. 常用不定积分

Posted by haifeng on 2014-12-23 20:25:34 last update 2022-04-26 08:56:59 | Answers (0) | 收藏


这里 $a > 0$.

\[
\int\frac{1}{t^2-a^2}\mathrm{d}t=\frac{1}{2a}\ln\biggl|\frac{t-a}{t+a}\biggr|+C,
\]

\[
\int\frac{1}{t^2+a^2}\mathrm{d}t=\frac{1}{a}\arctan\frac{t}{a}+C,
\]

27. 求 $\int\frac{x^2+1}{x^4+1}dx$

Posted by haifeng on 2014-12-23 20:09:56 last update 2014-12-23 20:16:34 | Answers (2) | 收藏


\[\int\frac{x^2+1}{x^4+1}dx\]


用类似的方法, 求

\[\int\frac{x^2-1}{x^4+1}dx\]

28. 求 $\int\frac{x^2}{(1-x)^{100}}dx$.

Posted by haifeng on 2014-12-23 19:58:59 last update 2014-12-23 19:58:59 | Answers (1) | 收藏


\[\int\frac{x^2}{(1-x)^{100}}dx.\]

29. 求不定积分 $\int\frac{1+\sin x}{1-\sin x}dx$

Posted by haifeng on 2014-12-22 22:30:47 last update 2014-12-22 22:30:47 | Answers (2) | 收藏


求不定积分

\[\int\frac{1+\sin x}{1-\sin x}dx\]

30. 求不定积分 $\int\sqrt{\frac{1+x}{1-x}}dx$

Posted by haifeng on 2014-12-22 20:45:10 last update 2014-12-22 20:45:10 | Answers (2) | 收藏


求不定积分

\[\int\sqrt{\frac{1+x}{1-x}}dx.\]

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