问题

Questions in category: 导数及微分 (Derivatives and differentials).

证明: 当 $x > 0$ 时, $e^{\frac{x}{x+1}} < (1+\frac{1}{x})^x < e$.

Posted by haifeng on 2022-11-10 13:21:28 last update 2022-11-10 13:21:28 | Answers (1) | 收藏

证明: 当 $x > 0$ 时,

\[e^{\frac{x}{x+1}} < (1+\frac{1}{x})^x < e.\]