Posted by haifeng on 2019-02-27 20:53:53 last update 2019-09-05 14:19:18 | Answers (0) | 收藏
求不定积分
\[\int\frac{2(1-u)}{2u+u^2 e^{-u}}du\]
Note that
\[ \frac{2(1-u)}{2u+u^2 e^{-u}}=\frac{1}{u}-\frac{e^{-u}+2}{ue^{-u}+2} \]
