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Questions in category: 初等数论 (Elementary Number Theory).

二次互反律(Quadratic Reciprocity Law)

Posted by haifeng on 2016-04-05 19:46:28 last update 2016-04-05 19:46:28 | Answers (0) | 收藏


\[
\Bigl(\frac{p}{q}\Bigr)\Bigl(\frac{q}{p}\Bigr)=(-1)^{\frac{p-1}{2}\cdot\frac{q-1}{2}}
\]