[Bug] 求解一元二次方程
版本 v0.551
>> solve(x^2+1==0)
这是一个一元二次方程.
x^2+1 == 0
solution>
x1 = 2.00000000*i/2-/(2)
x2 = -2.00000000*i/2-/(2)
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>> :mode fraction
Switch into fraction calculating mode.
e.g., 1/2+1/3 will return 5/6
>> solve(x^2+1==0)
这是一个一元二次方程.
x^2+1 == 0
Delta=b^2-4ac=-4
sqrt(Delta)=2*i
solution>
x1 = (+2*i)/2
x2 = (-2*i)/2
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