Answer

问题及解答

轮换的性质

Posted by haifeng on 2011-08-09 17:05:24 last update 2011-08-09 17:05:24 | Edit | Answers (0)

$(i_1i_2\cdots i_s)=(i_1i_2)(i_1i_3)\cdots(i_1i_s)$;
若 $\alpha\in S_n$, 则 $\alpha^{-1}(i_1i_2\cdots i_s)\alpha=i_1^\alpha i_2^\alpha\cdots i_s^\alpha$, 这里 $i_j^\alpha$ 指 $\alpha(i_j)$.