找到 $N$, 使得 $\sum\limits_{n=1}^{N}\dfrac{1}{n}<2\pi$, 但 $\sum\limits_{n=1}^{N+1}\dfrac{1}{n}>2\pi$.
找到 $N$, 使得 $\sum\limits_{n=1}^{N}\dfrac{1}{n}<2\pi$, 但 $\sum\limits_{n=1}^{N+1}\dfrac{1}{n}>2\pi$.
Answer: $N=300$.
Answer
问题及解答
1
启动 Sowya, 输入 :mode clox 进入编程模式.
{
fun f(){
var N=0;
var sum=0;
var pi=3.141592653589793238462643383279;
pi=2*pi;
while(sum<pi) {
N=N+1;
sum=sum+1/N;
}
print "N=",N-1;
}
}