问题及解答

>> :version

Version: 0.601

>> solve(x^2-6x+34==0)

这是一个一元二次方程.

  x^2-6x^1+34 == 0

solution>
        x1 = (6+1*-1^0*2^1*5^1*sqrt(1*-1))|2
        x2 = (6-(1*-1^0*2^1*5^1*sqrt(1*-1)))|2

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已解决.   2024-5-29

>> solve(x^2+3/2x-2==0)

这是一个一元二次方程.

  x^2+3|2x^1-2 == 0

solution>
        x1 = -3|4+sqrt(41)|2/2
        x2 = -3|4-sqrt(41)|2/2

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