Answer

问题及解答

证明 $\text{dgr}(m+n)=\text{dgr}(\text{dgr}(m)+\text{dgr}(n))$.

Posted by haifeng on 2015-05-09 16:46:24 last update 2016-10-27 10:58:02 | Edit | Answers (1)

设 $m,n$ 是两个正整数, 证明

\[
\begin{aligned}
\text{dgr}(m+n)&=\text{dgr}(\text{dgr}(m)+\text{dgr}(n)),\\
\text{dgr}(m\cdot n)&=\text{dgr}(\text{dgr}(m)\cdot\text{dgr}(n)),\\
\end{aligned}
\]

其中 $\text{dgr}(n)$ 是指数字 $n$ 的 digital root.

 

作为推论,

\[
\text{dgr}(n^k)=\text{dgr}\bigl(\text{dgr}^k(n)\bigr),\quad k\in\mathbb{Z}^{+}.
\]


Reference: http://en.wikipedia.org/wiki/Digital_root


The digital root of a sum is always equal to the digital root of the sum of the summands' digital roots

1

Posted by haifeng on 2016-10-27 10:53:04

根据 digital root 的定义或性质

\[
\mathrm{dgr}(n)=1+((n-1)\mod 9),
\]

可知

\[
\mathrm{dgr}(m+n)=\mathrm{dgr}(\mathrm{dgr}(m)+\mathrm{dgr}(n)).
\]